Web;display it;calculate the sum SUB BL,30h;change BL to a right value for calculation SUB CL,30h;change CL to a right value for calculation ADD BL,CL; add the numbers up and store the sum in BL ADD BL,30h;change the result in BL to hex value;display the result MOV AH,2;display character function MOV DL,BL;character is the one stored in BL INT 21h ... Web添加ax,30h mov dx,ax mov ah,02h int 21h 第三个错误是,看起来您似乎希望显示一个由两位数字组成的平均等级,并对DOS.PrintCharacter函数02h进行一次调用。 对于这个简单的练习,我们可以假设被试的数量和分数都是 ,单数数字, 。
100 years of lipstick in 30 sec 🔥👄💯💄 #shortvideo #youtubeshorts # ...
WebApr 9, 2024 · mov al, 30h ; 将30h加载到al中 mov bl, al ; 将al中的值存入bl and bl, 0fh ; 将bl中的低4位清零 shr al, 4 ; 将al中的低4位右移4位 or al, 30h ; 将al中的低4位置为3 or bl, al ; 将al中的值与bl相或 mov al, bl ; 将bl中的值存入al WebFind a health facility near you at VA Detroit Healthcare System, and manage your health online. Our health care teams are deeply experienced and guided by the needs of … city basketball recklinghausen
Solved 8086 language org 100h include
This addressing mode uses a base register either BX or BP and a displacement value to calculate physical address. Physical Address= Segment Register (Shifted to left by 1) + Effective address The effective address is the sum of offset register and displacement value. The default segments for BX and BP are DS … See more This mode involves the use of registers. These registers hold the operands. This mode is very fast as compared to others because CPU doesn’t need to access memory. CPU can … See more In this mode, there are two operands. One is a register and the other is a constant value. The register comes quickly after the op code. For example: 1. The instruction MOV AX, 30H copies … See more The register indirect addressing mode uses the offset address which resides in one of these three registers i.e., BX, SI, DI. The sum of offset address and the DS value shifted by one position generates a physical address. For … See more It loads or stores the data from memory to register and vice versa. The instruction consists of a register and an offset address. To compute … See more WebUse the following data definitions for this problem: .data myBytes BYTE 40h, 30h, 20h, 10h myWords WORD 10 DUP (00ABh), 2000h myString BYTE "ABCDEFGHI" myDword DWORD 12345678h (A) What will be the value of EAX after each of the following instructions execute? [5] a. What is the size of individual elements of myBytes in bytes? b. WebJun 28, 2010 · mov al,bl;move bl to al to make it the dividend, the sum is stored in bl sub al,30h;subtract 30h to make it number mov bl,10;move 10 to bl. div bl;divide to get the … dicks sports store florence